Display employees and their manger name in SQL

This is one of the most asked SQL interview Question that write a SQL Query to display Employees and Manager name of the employee.

Let’s create a sample table using below scripts.

CREATE TABLE EmployeeDetails
(EmpID INT, EMPName VARCHAR(100), MailID VARCHAR(50), MANAGER_ID INT);

INSERT INTO EmployeeDetails 
(EmpID, EMPName, MailID, MANAGER_ID) VALUES
(101, 'Jhone Henery', 'jh@xyz.com', 0),
(102, 'Mohit Singh', 'ms@xyz.com', 101),
(103, 'Jenlia jr.', 'jjr@xyz.com', 101),
(104, 'Akash Kumar', 'ak@xyz.com', 101),
(105, 'Mangesh Singh', 'ms@xyz.com', 103),
(106, 'Ajay Agarwal', 'aa@xyz.com', 103),
(107, 'Punit Negi', 'pn@xyz.com', 102),
(108, 'Suraj Gupta', 'sg@xyz.com', 105),
(109, 'Ranjit Singh', 'rs@xyz.com', 105),
(110, 'Manmeet kumar Singh', 'mks@xyz.com', 107);

Now, we have created a table name EmployeeDetails and inserted some sample records into this table.

SELECT * FROM EmployeeDetails;

Now to display employees and their managers name in SQL, we need to use self-join on the EmployeeDetails table as shown below.

SELECT emp.EMPID, emp.EMPName, emp.MailID, Mgr.EMPName AS MangerName 
FROM EmployeeDetails emp 
LEFT OUTER JOIN EmployeeDetails mgr
ON emp.manager_id = mgr.empid

Let’s understand the above SQL Query, it uses the left outer join to match each employees with their corresponding manager based on the Manager_ID in the EmployeeDetails table and returns null for non matching Manager_ID.

Let’s execute the query and you can see the output. It returns the employees and their managers name.

 

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