SQL DATEFROMPARTS

SQL DATEFROMPARTS() function is a date function that returns a date value that maps to a year, month, and day values.

SYNTAX

DATEFROMPARTS (year, month, day)

The DATEFROMPARTS function accepts three parameters:

Year is an integer

Month is an integer, any month value between 1 to 12.

Day is an integer, any day between 1 to 31

Lets look at an example of using DATEFROMPARTS function in SQL.

Following DATEFROMPARTS function returns a date for given month, year, and day .

declare @yr as int ,@month as int ,@day as int

set @yr =2017
set @month =12
set @day =31
select DATEFROMPARTS(@yr, @month, @day) as Date

To get a date from given year, month, day without using a DATEFROMPARTS function, you can use following T-SQL Code.

declare @yr as int ,@month as int ,@day as int

set @yr =2017
set @month =12
set @day =31
select CAST(@yr as varchar) + ‘-‘ + cast ( @month as varchar) + ‘-‘ + cast ( @day as varchar) as date

declare @yr as int, @month as int, @day as int
set @yr = 2017
set @month = null
set @day = 31

select DATEFROMPARTS(@yr, @month, @day) as Date

DATEFROMPARTS returns an error for any invalid day, month and year value.

Lets pass an invalid value for month that is 34 to DATEFORMPARTS function.

declare @yr as int, @month as int, @day as int
set @yr =2017
set @month = 34
set @day = 31

select DATEFROMPARTS(@yr, @month, @day) as Date

As you can see, it gives an error saying cannot construct data type date, some of the arguments have values which are not valid.

Also Read..

SQL DateName()